Impl C solution to problem
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2
c_impl/.gitignore
vendored
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c_impl/.gitignore
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RunLengthEncoding
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src/*.o
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20
c_impl/Makefile
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c_impl/Makefile
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SOURCES = src/main.c src/map.c
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OBJECTS = $(subst .c,.o,$(SOURCES))
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COMMON_FLAGS = -Wall -Wextra -Wpedantic
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ifdef DEBUG
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CFLAGS = $(COMMON_FLAGS) -O0 -g
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else
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CFLAGS = $(COMMON_FLAGS) -O3 -DNDEBUG
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endif
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all: RunLengthEncoding
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RunLengthEncoding: $(OBJECTS)
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$(CC) -o RunLengthEncoding $^
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.PHONY:
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clean:
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rm -f RunLengthEncoding
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rm -f src/*.o
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28
c_impl/src/main.c
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c_impl/src/main.c
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#include <stdio.h>
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#include <string.h>
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#include <stdlib.h>
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#include "map.h"
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/*
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* Requires keeping track of how many times each character is seen. It looks
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* like it may require a map structure due to the fact that the given list is
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* not necessarily in order.
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*/
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int main(int argc, char **argv) {
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if(argc != 2) {
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return 1;
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}
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CharMap map = initMap();
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for(char *str = argv[1]; *str != 0; ++str) {
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insertMap(map, *str);
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}
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printMapContents(map);
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cleanupMap(map);
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return 0;
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}
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81
c_impl/src/map.c
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c_impl/src/map.c
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#include "map.h"
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#include <stdlib.h>
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#include <string.h>
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#include <stdio.h>
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CharMap initMap() {
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CharMap map = (CharMap){0, MAP_INIT_SIZE, 0};
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map.buckets = calloc(MAP_INIT_SIZE, sizeof(Bucket));
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for(unsigned int i = 0; i < MAP_INIT_SIZE; ++i) {
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map.buckets[i].array = calloc(MAP_BUCKET_INIT_SIZE, sizeof(Item));
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map.buckets[i].capacity = 4;
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}
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return map;
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}
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void cleanupMap(CharMap map) {
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for(unsigned int i = 0; i < map.capacity; ++i) {
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free(map.buckets[i].array);
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}
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free(map.buckets);
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}
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void insertMap(CharMap map, char item) {
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// TODO recreate buckets when limit is reached
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// though this is for practice, so it's not really necessary
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unsigned int bucket_id = hasher(item) % map.capacity;
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// first check if char exists in bucket
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unsigned int i = 0;
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for(; i < map.buckets[bucket_id].size; ++i) {
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if(map.buckets[bucket_id].array[i].key == item) {
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break;
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}
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}
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if(i < map.buckets[bucket_id].size) {
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// exists in bucket, just increment the value
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map.buckets[bucket_id].array[i].value += 1;
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} else {
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// does not exist, check if capacity is there for new entry
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// and increase capacity if there isn't
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if(map.buckets[bucket_id].capacity == map.buckets[bucket_id].size) {
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Item *new_array = malloc(sizeof(Item)
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* map.buckets[bucket_id].capacity * 2);
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memcpy(new_array, map.buckets[bucket_id].array, map.buckets[bucket_id].capacity * sizeof(Item));
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free(map.buckets[bucket_id].array);
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map.buckets[bucket_id].array = new_array;
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map.buckets[bucket_id].capacity *= 2;
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}
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map.buckets[bucket_id].array[map.buckets[bucket_id].size++] = (Item){item, 1};
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}
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}
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unsigned int getMap(CharMap map, char item) {
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unsigned int bucket_id = hasher(item) % map.capacity;
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for(unsigned int i = 0; i < map.buckets[bucket_id].size; ++i) {
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if(map.buckets[bucket_id].array[i].key == item) {
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return map.buckets[bucket_id].array[i].value;
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}
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}
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return 0;
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}
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void printMapContents(CharMap map) {
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for(unsigned int i = 0; i < map.capacity; ++i) {
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for(unsigned int j = 0; j < map.buckets[i].capacity; ++j) {
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if(map.buckets[i].array[j].value > 0) {
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printf("%c has %d entries\n", map.buckets[i].array[j].key,
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map.buckets[i].array[j].value);
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}
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}
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}
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}
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unsigned int hasher(char item) {
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// really crappy hasher
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return (((unsigned int)item) + 17) * 59;
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}
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40
c_impl/src/map.h
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c_impl/src/map.h
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#ifndef PRACTICE_MAP_H
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#define PRACTICE_MAP_H
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/*
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* map contains a limited amount of buckets. Hashing the key will associate that
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* key to a given bucket. When multiple keys are associated with the same
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* bucket, use an array to hold multiple. Requries keys be hashable and
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* equatable.
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*/
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#define MAP_LIMIT 0.75
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#define MAP_INIT_SIZE 32
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#define MAP_BUCKET_INIT_SIZE 4
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typedef struct Item {
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char key;
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unsigned int value;
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} Item;
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typedef struct Bucket {
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Item *array;
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unsigned int capacity;
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unsigned int size;
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} Bucket;
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typedef struct CharMap {
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Bucket *buckets;
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unsigned int capacity;
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unsigned int size;
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} CharMap;
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CharMap initMap();
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void cleanupMap(CharMap map);
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void insertMap(CharMap map, char item);
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unsigned int getMap(CharMap map, char item);
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void printMapContents(CharMap map);
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unsigned int hasher(char item);
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#endif
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1
problem
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1
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programmingpraxis.com February 9, 2021
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