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Experimental: remove use of mutex when threaded

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In theory, it seems that each pixel is only written to once, regardless
of how many threads there are. Theoretically, this means that locks are
not required.
This commit is contained in:
Stephen Seo 2021-08-24 18:30:15 +09:00
parent 075aab2a57
commit 13bf59dcc8
1 changed files with 2 additions and 2 deletions
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4
example02_threaded_raytracing/src/rayTracer.cpp
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@ -429,7 +429,7 @@ Ex02::RT::Image Ex02::RT::renderColorsWithSpheres(unsigned int outputWidth,
} }
} else { } else {
std::vector<std::thread> threads; std::vector<std::thread> threads;
std::mutex mutex; // std::mutex mutex;
unsigned int range = outputHeight / threadCount; unsigned int range = outputHeight / threadCount;
for (unsigned int threadIdx = 0; threadIdx < threadCount; ++threadIdx) { for (unsigned int threadIdx = 0; threadIdx < threadCount; ++threadIdx) {
unsigned int start = range * threadIdx; unsigned int start = range * threadIdx;
@ -444,7 +444,7 @@ Ex02::RT::Image Ex02::RT::renderColorsWithSpheres(unsigned int outputWidth,
yIteration(y, mutex); yIteration(y, mutex);
} }
}, },
start, end, &mutex)); start, end, nullptr));
} }
for (std::thread &thread : threads) { for (std::thread &thread : threads) {
thread.join(); thread.join();